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Home /Doubts and Solutions/CBSE/Class 12/Chemistry/Solutions/Association And Dissociation

Association And Dissociation Free Doubts and Solutions

CBSE - XII Science - Chemistry - Solutions

The formula of degree of dissociation

Asked by kalandi.charan.407 8th February 2024, 1:42 PM
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CBSE - XII Science - Chemistry - Solutions

HOW TO FIND VANT OF FACTOR  

Asked by RAJAGUPTA 1st January 2020, 8:19 PM
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CBSE - XII Science - Chemistry - Solutions

Solution

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CBSE - XII Science - Chemistry - Solutions

Value of Van't Hoff factor if CH3COOH 60% dissociates and 40% dimerized is–(1) 1.2, (2) 1.4, (3) 1.6, (4) 1.8

Asked by patra04011965 18th July 2019, 4:07 PM
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CBSE - XII Science - Chemistry - Solutions

I know that answer is (a) but please explain the reason in detail

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CBSE - XII Science - Chemistry - Solutions

why is the i value of sugar and glucose 1

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CBSE - XII Science - Chemistry - Solutions

when to use R=8.314 and  R=0.008314

Asked by mangesh 25th June 2016, 1:18 PM
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CBSE - XII Science - Chemistry - Solutions

Predict the Boiling point of solution prepared by dissolving 25.0g of urea and 25.0 g of thiourea in 100 gram of water. Given for water Kb= 0.52 K Kg mol-1 and Boiling point of pure water is 373.15 K.

Asked by Topperlearning User 20th June 2016, 3:51 PM
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CBSE - XII Science - Chemistry - Solutions

0.216molal solution of Cadmium sulphate is prepared in 1000gram of water. The depression in freezing point was measured to be 0.284K. Calculate the Vant hoff factor. The Cryoscopic constant for water is 1.86K Kg mol-1.

Asked by Topperlearning User 20th June 2016, 3:50 PM
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CBSE - XII Science - Chemistry - Solutions

What does the line, ' Depending on the vapour pressures of the pure components 1 and 2, total vapour pressure over the solution decreases or increases with the increase of the mole fraction of component 1' ?

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CBSE - XII Science - Chemistry - Solutions

how to find equivalent weight?
 

Asked by Dave Agresha 8th May 2015, 4:46 PM
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CBSE - XII Science - Chemistry - Solutions

A 0.1 molar NaCl soln. exerts an osmotic pressure of 4.82 atm at 27 degree of dissociation of Nacl.vol=10l w=58.5

Asked by Subhashree Lenka 5th May 2015, 11:49 AM
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CBSE - XII Science - Chemistry - Solutions

Consider separate solutions of 0.5 M CH3OH, 0.250 M KCl (aq) and 0.125 M Na3PO4
  • (aq). Arrange the above solutions in the increasing order of their Van’t Hoff factor.Give reason also ...

Asked by Om Prakash Arya 7th February 2015, 5:56 AM
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CBSE - XII Science - Chemistry - Solutions

How can we find the vant Hoff factor in the following question-
 
calculate the boiling point elevation for a solution prepared by adding 10g of CaCl2 in 200g of water?
(Kb for water =0.512K/m  , atomic weight of Ca=40,Cl=35.5)

Asked by Karishma 31st December 2014, 9:54 PM
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CBSE - XII Science - Chemistry - Solutions

How to find out when to use 1-alpha is approximately 1 in the Ka equation? Also what is Solubility product, explain clearly.

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CBSE - XII Science - Chemistry - Solutions

How to find out when to use 1-alpha is approximately i in the Ka equation? Also what is Solubility product, explain clearly.

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CBSE - XII Science - Chemistry - Solutions

Equimolar solution of glucose and Common salt are not isotonic. Why?

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CBSE - XII Science - Chemistry - Solutions

Calculate the amount of NaCl must be added to 1000 ml of water so as to reduce its freezing point by two Kelvin. For water Kf = 1.86 K Kg mol-1 , give that the density of water is 1.0 g ml-1 and NaCl is completely dissociated.

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CBSE - XII Science - Chemistry - Solutions

The freezing point of 0.1molal Potassium chloride solution is 0.372 oC what conclusion can be drawn about its molecular state? For water Kf = 1.86 K Kg mol-1.

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - XII Science - Chemistry - Solutions

molar solution of common salt exerts osmotic pressure of 1.535 atm at 100K. Calculate its degree of dissociation. Had NaCl not dissociated its osmotic pressure would have been.

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - XII Science - Chemistry - Solutions

Predict the Boiling point of solution prepared by dissolving 3.42g of sugarcane in 100 gram of water. Given for water Kb= 0.52 K Kg mol-1 and Boiling point of pure water is 373.15 K.

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - XII Science - Chemistry - Solutions

weak electrolyte AB is 5% dissociated in aqueous solution. What is the freezing point of a 0.100 molal aqueous solution of AB? For water Kf = 1.86 K Kg mol-1.

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - XII Science - Chemistry - Solutions

0.02molal solution of acetic acid is 3% dissociated at 25oC calculate the Osmotic pressure of the solution.

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CBSE - XII Science - Chemistry - Solutions

Calculate the amount of KCl must be added to one kilogram of water so as to reduce its freezing point by two Kelvin. For water Kf = 1.86 K Kg mol-1.

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CBSE - XII Science - Chemistry - Solutions

substance X forms trimer when added to Benzene calculates the freezing point of the 0.25 molal solution. The degree of association of the solute is found to be 0.80. The freezing point of the benzene is 5.5oC and its Cryoscopic constant is 5.12 K m-1.

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - XII Science - Chemistry - Solutions

Two molar solution of potassium Ferro cyanide has degree of dissociation 0.70 at 300K.Find out the osmotic pressure of the solution.

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - XII Science - Chemistry - Solutions

0.90 g of an  1:2 electrolyte was dissolved in 87.90 g of benzene. This raised the boiling point of benzene by 0.250 C. If the molecular mass of the electrolyte is 103.0molar calculate the molal elevation constant for benzene. Given that the solute dissociate with degree of dissociation 0.25.

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - XII Science - Chemistry - Solutions

Calculate the freezing point of a solution containing 0.52 g glucose (C6H12O6) dissolved in 80.20g water. For water Kf = 1.86 K Kg mol-1

Asked by Topperlearning User 4th June 2014, 1:23 PM
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CBSE - XII Science - Chemistry - Solutions

At 25 degree celcius benzene and toulene have density .879 and .876 g/ml respectively . assuming that benzene and toulene are ideal solutions. establish the equation alpha(degree of association or dissociation) = 1/100[.879v + .867 (100-v)] where v is the volume of benzene 

Asked by PratibhaPandey 19th May 2014, 2:59 PM
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