ICSE Class 10 Answered
ABC is an isosceles triangle in which AB=AC=10 cm. ,BC=12 cm. PQRS is a rectangle inside the isosceles triangle. if PQ=SR=Ycm. and PS=QR=2X cm.,then prove that X=6-3Y/4.
Asked by aditisinha952003 | 17 Feb, 2019, 02:32: PM
Expert Answer
since BC = 12 cm and QR = 2X cm, we have BQ = [ 12 - 2X ]/2 = (6-X) cm
since PS is parallel to BC,
Hence BP = [ 10 - (5X)/3 ]
In right angled triangle BPQ, we have, Y2 = [ 10 - (5X)/3 ]2 - (6-X)2 = [ 10 - (5X)/3 + 6 - X ] [10 - (5X)/3 - 6 +X ] ..............(1)
By simplifying the above expression (1), we get, 9Y2 = 16 (6-X)2 or (3Y/4) = (6-X) or X = [ 6 - (3Y)/4 ]
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