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A sound absorber attentutes the sound level by 20dB . The intensity decrease by what factor?
Asked by sharadhabakam8 | 14 May, 2021, 12:02: PM
Expert Answer
Attenuated sound Intensity β in decibel is given as
β =10 log ( I / Io ) = 20
where I is attenuated intensity ( W / m2 ) and Io is initial unattenuated sound intensity
log ( I / Io ) = 2
( I / Io ) = 102 = 100
Io = (1/100) I
Intensity decreases by a factor (1/100)
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