NEET Class neet Answered
a rock is thrown straight up with twice the initial the velocity of another. how much higher will the first rock be at its apex?
Asked by meghanaprabhu1612 | 22 Oct, 2020, 07:56: PM
Expert Answer
Let rock-1 is thrown upwards with speed 2u and rock-2 is thrown upward with speed u.
Height h1 reached by the first rock = ( 2u )2 / (2g) = ( 4 u2 ) / ( 2g )
Height h2 reached by the second rock = u2 / (2g) = u2 / (2g )
First rock will reach 4 times of height reached by second rock
Answered by Thiyagarajan K | 22 Oct, 2020, 08:39: PM
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