NEET Class neet Answered
A particle is suspended using thread of length L. If V(L)= √(3gL), then find maximum height attained by the particle.
Asked by patra04011965 | 09 Oct, 2019, 07:59: AM
Expert Answer
Given velocity is maximum velocity at lowest position of particle.
Then maximum height h reached by particle is obtained by equating maximum kinetic energy to maximum potential energy.
(1/2) m v2 = m g h or h = v2 / g
hence maximum height reached by particle, h = (3 g L )/ g = 3L
Answered by Thiyagarajan K | 09 Oct, 2019, 10:54: AM
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