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NEET Class neet Answered

A junction diode of internal resistance 20 ohm is used for half wave rectification.if the applied voltage has a peak value of 50V and load resistance is 800 ohm.then the dc power is?
Asked by bhavanamadhumohanan | 17 Apr, 2019, 10:45: PM
answered-by-expert Expert Answer
Net resistance of the circuit  = 800+20 = 820ohm
 value of current = 50/820 = 0.061 A
Power consumption  = 1/2 ×( V×I)
P = 0.5 × 0.061×50 
 P = 1.525 watt
Answered by Ankit K | 17 Apr, 2019, 11:26: PM
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