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Maharashtra Class 10 Answered

A doctor is called to see a sick child.  The doctor has prior infoeinform that 80% of sick children in that area have flu , while other 20% are sick with measles. Assume that there is no other disease in that area. A well-known symptom of measles is a rash. From the past records, it is known that, chances of having rashes given that sick child is suffering from measles is 0.95 . However, occasionally children with flu also develop rash, whose chances are 0.08. Upon examining the child, the doctor finds a rash. What is the probability that the child has measles?
Asked by gulreztamkeensiddiqui | 08 Feb, 2019, 11:05: PM
answered-by-expert Expert Answer
Probability space of space having space flu equals straight P open parentheses straight f close parentheses equals 0.8 Probability space of space having space measles equals straight P open parentheses straight m close parentheses equals 0.2 Probability space of space getting space rashes space given space measles equals straight P open parentheses straight R over straight m close parentheses equals 0.95 Probability space of space getting space rashes space given space flu equals straight P open parentheses straight R over straight f close parentheses equals 0.08 now comma space probability space that space measles space are space the space result space of space rashes equals straight P open parentheses straight m over straight R close parentheses equals fraction numerator straight P open parentheses straight m close parentheses. straight P open parentheses straight R over straight m close parentheses over denominator straight P open parentheses straight m close parentheses. straight P open parentheses straight R over straight m close parentheses plus straight P open parentheses straight f close parentheses straight P open parentheses straight R over straight f close parentheses end fraction equals fraction numerator 0.2 cross times 0.95 over denominator 0.2 cross times 0.95 plus 0.8 cross times 0.08 end fraction equals 0.748
Answered by Arun | 11 Feb, 2019, 11:09: AM

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