ICSE Class 10 Answered
A cell of EMF 2V and internal resistance 1ohm is connected with two wires of resistances 2ohm and 3ohm in parallel. Find the current in each wire.
Asked by www.utkarshdubey1408 | 20 Apr, 2022, 10:52: PM
Expert Answer
Given that,
Internal resistance of cell, r = 1 Ohm
EMF of cell, V = 2 V
Now,
The effective reisistance of wires connected in parallel combination will be given as
Hence the amount of current flowing through given combination will be
I = V(Rf + r)
Now, the potential drop across parallel combination of wires will be
Vf = IRf =0.9 x 1.2 = 1.08 V
Thus,
Current through 3 Ohm resistance will be
I2 = Vf /R2 = 1.08 / 3 = 0.36 A
Similarly, Current through 2 Ohm resistance will be
I1 = Vf /R1 = 1.08 / 2 = 0.54 A
Answered by Jayesh Sah | 23 Apr, 2022, 08:11: PM
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