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ICSE Class 10 Answered

A B and C  are acute angles of triangle ABC. Prove that tan(A+B/2) = cot C/2
Asked by Parvez | 26 Feb, 2016, 10:54: PM
answered-by-expert Expert Answer
begin mathsize 12px style For space straight a space triangle space ABC comma space angle straight A plus angle straight B plus angle straight C equals 180 degree rightwards double arrow angle straight A plus angle straight B equals 180 degree minus angle straight C rightwards double arrow fraction numerator angle straight A plus angle straight B over denominator 2 end fraction equals fraction numerator 180 degree minus angle straight C over denominator 2 end fraction rightwards double arrow fraction numerator angle straight A plus angle straight B over denominator 2 end fraction equals 90 degree minus fraction numerator angle straight C over denominator 2 end fraction rightwards double arrow tan open parentheses fraction numerator angle straight A plus angle straight B over denominator 2 end fraction close parentheses equals tan open parentheses 90 degree minus fraction numerator angle straight C over denominator 2 end fraction close parentheses rightwards double arrow tan open parentheses fraction numerator angle straight A plus angle straight B over denominator 2 end fraction close parentheses equals cot open parentheses fraction numerator angle straight C over denominator 2 end fraction close parentheses space left parenthesis Proved right parenthesis end style
Answered by satyajit samal | 29 Feb, 2016, 01:44: AM
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ICSE 10 - Maths
tan A + sec A -1 / tan A - sec A +1 = 1+ sinA / cos A     
Asked by heermurjani | 05 Apr, 2019, 04:32: PM
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