CBSE Class 12-science Answered
49th sum
Asked by lovemaan5500 | 10 Feb, 2020, 11:51: PM
Expert Answer
integration of (sinx + cosx)dx/√(9 + 16sin2x)
cosx - sinx = t → -(sinx + cosx)dx = dt
(cosx - sinx)2 = t2
cos2 x + sin2 x - 2sinxcosx = t2
1 - sin2x = t2
sin2x = 1 - t2
Integrate it further using appropriate formula.
Answered by Sneha shidid | 11 Feb, 2020, 10:00: AM
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