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CBSE Class 12-science Answered

16. The work function for cesium is 19 3.43 10  J. What is the kinetic energy of an electron liberated by radiation of 550 nm? What is stopping voltage? How many electrons are generated if the total energy absorbed at 550 nm is 1.00 10 J 3  ?
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Asked by pariveshnath2004 | 04 Aug, 2020, 02:45: PM
answered-by-expert Expert Answer
K i n e t i c space e n e r g y space o f space a n space e l e c t r o n equals E minus W o r k space f u n c t i o n
E n e r g y space o f space r a d i a t e d space l i g h t comma E equals fraction numerator h c over denominator lambda end fraction
E equals fraction numerator 6.626 cross times 10 to the power of negative 34 end exponent cross times 3 cross times 10 to the power of 8 over denominator 550 cross times 10 to the power of negative 9 end exponent end fraction equals 3.61 cross times 10 to the power of negative 19 end exponent J
K E equals 3.61 cross times 10 to the power of negative 19 end exponent J minus 3.43 cross times 10 to the power of negative 19 end exponent J
K E equals 0.18 cross times 10 to the power of negative 19 end exponent J
K E equals e V subscript 0
W h e r e space V subscript 0 space i s space t h e space s t o p p i n g space v o l t a g e
0.55 cross times 10 to the power of negative 19 end exponent J equals 1.6 cross times 10 to the power of negative 19 end exponent V subscript 0
V subscript 0 equals 0.113 V
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