x = 3 + square root of 2 , y = fraction numerator 1 over denominator 3 square root of 2 end fraction  find the value of left parenthesis x plus 1 over y right square bracket cubed and x to the power of 2 space end exponent minus space y squared

Asked by uniquecraftsdas | 19th Jul, 2019, 12:14: AM

Expert Answer:

x = 3 + √2 and y = 1/3√2
then y = 3√2
(x + 1/y)3 = (3 + √2 + 3√2)3 
                = (3 + 4√2)3 
                = 33 + 3 × (3)2 × 4√2 + 3 × 3 × (4√2)2 + (4√2)3
Solving we get (x + 1/y)3 = 315 + 236√2

Answered by Sneha shidid | 19th Jul, 2019, 09:38: AM