JEE Class main Answered
Work done against the gravity by taking a 10kg block to height 1m in 1sec will be?here why we take external force equal to mg
Asked by ashutosharnold1998 | 28 Sep, 2019, 09:58: PM
Expert Answer
workdone = Force × distance = mg × h = 10×9.8×1 = 98 J
m = mass of load, g = acceleration due to gravity, h = distance
power = Rate of workdone = 98 J / 1 s = 98 W
work is done to lift the 10 kg load against gravitational force .
Gravitational force acting on a mass m is m×g
Answered by Thiyagarajan K | 29 Sep, 2019, 07:29: AM
Application Videos
-
Elastic potential energy_Restoring force and spring con ...
In this video, the restoring force and spring constant is explained. The vi... -
Expression of Elastic potential energy_2
This video describes the potential energy of spring when it is compressed o... -
Potential Energy Curve
This video describes the potential energy curve and ature of forces based o... -
Work done by static friction
This video describes effect of static friction on the work done by the obje... -
Work done in conservative field - 1
The concept of conservative field, types of conservative forces and example...
JEE main - Physics
Asked by sohan123asiwal | 12 May, 2024, 05:52: PM
ANSWERED BY EXPERTJEE main - Physics
Asked by pranav10022007 | 12 May, 2024, 10:05: AM
ANSWERED BY EXPERTJEE main - Physics
Asked by anupriya23102006 | 09 May, 2024, 04:09: PM
ANSWERED BY EXPERTJEE main - Physics
Asked by ashwinskrishna2006 | 07 May, 2024, 05:33: PM
ANSWERED BY EXPERTJEE main - Physics
Asked by srkgb8018 | 05 May, 2024, 10:12: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by sandhyapallapu22 | 03 May, 2024, 04:32: PM
ANSWERED BY EXPERTJEE main - Physics
Asked by gamingbadboy085 | 01 May, 2024, 06:28: PM
ANSWERED BY EXPERTJEE main - Physics
Asked by bhargavreddynellaballi | 30 Apr, 2024, 08:18: AM
ANSWERED BY EXPERTJEE main - Physics
Asked by ravichandraravula66 | 29 Apr, 2024, 11:20: AM
ANSWERED BY EXPERT
