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What is the solution of fraction numerator 1 minus 5 to the power of x over denominator 7 to the power of negative x end exponent minus 7 end fraction greater or equal than 0?
Asked by rishabhsankla1 | 03 Aug, 2020, 15:36: PM
answered-by-expert Expert Answer
(1-5x)/(7-x-7) >= 0 
fraction numerator 1 minus 5 to the power of straight x over denominator 7 to the power of negative straight x end exponent minus 7 end fraction greater or equal than 0 rightwards double arrow 1 minus 5 to the power of straight x greater or equal than 0 space and space 7 to the power of negative straight x end exponent minus 7 greater or equal than 0 space space OR space space 1 minus 5 to the power of straight x less or equal than 0 space and space 7 to the power of negative straight x end exponent minus 7 less or equal than 0 rightwards double arrow 1 greater or equal than 5 to the power of straight x space and space 7 to the power of negative straight x end exponent greater or equal than 7 space space OR space space 1 less or equal than 5 to the power of straight x space and space 7 to the power of negative straight x end exponent less or equal than 7 rightwards double arrow 5 to the power of straight x less or equal than 5 to the power of 0 space space and space space 7 to the power of negative straight x end exponent greater or equal than 7 to the power of 1 space space space OR space space 5 to the power of straight x greater or equal than 5 to the power of 0 space space and space space 7 to the power of negative straight x end exponent less or equal than 7 to the power of 1 rightwards double arrow straight x less or equal than 0 space and space straight x less or equal than negative 1 space space OR space space straight x greater or equal than 0 space and space straight x greater or equal than negative 1 rightwards double arrow straight x less or equal than negative 1 space space OR space space straight x greater or equal than 0 rightwards double arrow straight x element of left parenthesis negative infinity comma space minus 1 right square bracket space union left square bracket 0 comma space infinity right parenthesis
Answered by Renu Varma | 04 Aug, 2020, 11:25: AM

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