Water flows out through a circular pipe, whose internal diameter is 2 cm @ 0.7 m per second into a cylindrical tank, the radius of whose base is 40 cm.  By how much will the level of water rise in an hour?

Asked by jaychandran1967 | 31st Mar, 2017, 01:11: PM

Expert Answer:

begin mathsize 16px style Let space water space level space rises space in space 1 space hour space be space straight x space cm.
Volume space of space cylinder space equals πr squared straight h
straight r equals 1 space cm space and space straight h equals 0.7 space straight m equals 70 space cm
Water space is space flowing space at space the space rate space of space 0.7 space straight m divided by straight s
Volume space of space water space in space one space second space equals space 22 over 7 cross times 1 cross times 1 cross times 70 equals 220 space cm cubed
1 space hours equals 1 cross times 60 cross times 60 space equals space 1800 space seconds
in space half space hour space water space flow space will space be space 3600 cross times 220 equals 792000 space cm cubed
Volume space of space water space in space the space tank space after space an space hour equals space Volume space of space the space cylindrical space tank space the space radius space of space
base space 40 space cm space and space height space is space straight x space cm.
Volume space of space cylindrical space tank space equals space 22 over 7 cross times 40 cross times 40 cross times straight x equals 792000
straight x equals 157.5 space cm
end style

Answered by Sneha shidid | 31st Mar, 2017, 02:15: PM