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Urgent! please solve the problem in the given image with steps.
Asked by miaowmira1900 | 12 Aug, 2019, 01:21: AM
Voltage between Gate and Source, vGS = 5× R2 /( R1 + R2 )  = 5× 100/ 675.7 = 0.74 V

Drain current  iD = K( vGS - vT )2  =  1.16×10-3 ( 0.74 - 0.5 )2 = 67 μA

if vDS ≥ ( vGS - vT )   or  vDS ≥ (0.74 - 0.5 )   or  vDS ≥ 0.24 V , then voltage drop across RD ≤ ( 5-0.24)  V

Hence maximum voltage drop across RD = 4.76 V

since drain current is 67 μA ,  resistance RD = 4.76 V / 67 μA = 71.04 kΩ
Answered by Thiyagarajan K | 12 Aug, 2019, 07:29: AM

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