CBSE Class 12-science Answered
two wires of different material of length 50cm and 75cm and respective diameters 0.2mm and 0.1mm have resistance of o.8ohm and 1.5ohm respectively what is the ratio of specific resistance of material
Asked by bhushankr113 | 03 Jul, 2019, 12:28: PM
Expert Answer
Let resistance R1 = 0.8 Ω and R2 = 1.5 Ω .
R1 = ρ1 ×( L1 / A1 ) = 0.8 Ω .......................(1)
R2 = ρ2 ×( L2 / A2 ) = 1.5 Ω ......................(2)
where ρ, L and A are respective resistivity, Length and area of crosssection.
hence, ( ρ1 / ρ2 ) = (0.8/1.5)×(L2 / L1 )×(A1 /A2) = (0.8/1.5)×(75 / 50 )×(4 /1) = 3.2
Answered by Thiyagarajan K | 03 Jul, 2019, 02:51: PM
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