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two particles execute SHM of the same amplitude and frequency along the same straight line the past one another when going in opposite directions each time that displacement is half the amplitude what is the phase difference between them
Asked by rheavirginkar | 04 Mar, 2019, 11:55: AM
answered-by-expert Expert Answer
Using x = A sin(  ω t+ Φ) where all the symbols have usual meaning 
Using given data in this equation  and equating it, 
We get
A/2  = A sin(Φ)
Where Φ initial phase difference 
So Φ = π/6 or 30 degree
 
Opposite direction of shm means if one of the particle is moving from mean position to maximum amplitude point direction then other particle is moving toward mean position from maximum amplitude point. 
Answered by Ankit K | 04 Mar, 2019, 13:06: PM

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