JEE Class main Answered
Two large glass plate are placed vertically and parallel to each other inside a tank of water with separation between the plate is equals to 1 mm .Find the rise of water in the space between the plates surface tension of water equals 0.075 Nm^-1
Asked by Harshjaiswal9450 | 27 Apr, 2020, 12:26: PM
Expert Answer
Surface tension force is acting along the length l on both the plates.
Hence surface tension force = T × 2 l
surface tension force is balanced by weight of liquid column, l×h×d×ρ
where h is rise of water column, d is distance between plates and ρ is density
Hence we have, T × 2 l = l×h×d×ρ×g
h = 2T / ( d×ρ×g ) = ( 2 × 0.075 ) / ( 1 × 10-3 × 1000×9.8 ) = 0.0153 m ≈ 15 mm
Answered by Thiyagarajan K | 27 Apr, 2020, 02:43: PM
Application Videos
JEE main - Physics
Asked by sandhyapallapu22 | 03 May, 2024, 04:32: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by gamingbadboy085 | 01 May, 2024, 06:28: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by bhargavreddynellaballi | 30 Apr, 2024, 08:18: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ravichandraravula66 | 29 Apr, 2024, 11:20: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by kmani310507 | 28 Apr, 2024, 04:38: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by arivaryakashyap | 23 Apr, 2024, 10:40: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ratnadeep.dmr003 | 21 Apr, 2024, 11:06: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ksahu8511 | 19 Apr, 2024, 11:55: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by mohammedimroz | 13 Apr, 2024, 09:48: PM
ANSWERED BY EXPERT