to prove
Asked by | 20th Feb, 2009, 05:17: PM
Expert Answer:
(p x q). [(q x r) x (r x p)]
= (p x q). [ r ( (qxr).p ) - p ( (qxr).r ) ]
here (qxr) . r = 0 then
=(p x q). [ r ( (qxr).p ) ]
= (pxq).r [ q r p] ( [q r p ] = [p q r ] )
= [p q r ] [p q r ]
= [p q r ]2
Answered by | 20th Feb, 2009, 11:22: PM
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