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The vertices of triangle are a(-1,-1),b(2,3),c(4,2),then the greatest angle of triangle is
Asked by Njishang | 20 Mar, 2019, 21:48: PM
Expert Answer
Th triangle is plotted as per the given vertices.
Area of Δ = (1/2)[ -1(2-3)+4(3+1)+2(-1-2) ] = 11/2 sq.units
length of AC = b =
length of BC = a =
we have , (1/2)a b sin C = Δ , hence sin C = 2Δ /(a b ) = 11/(5√5) = 0.984
hence angle C = sin-1 (0.984) ≈ 80° . since C is obtuse angle, angle C = 180 -80 = 100°
Answered by Thiyagarajan K | 21 Mar, 2019, 07:47: AM
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