The value of direction cosine of two straight lines can satisfy the two equation, 3l+m+5n=0 & 6mn-2nl+5lm=0 . Find the angle between those lines.
Asked by rsjkumar2003 | 23rd Sep, 2019, 01:09: PM
Expert Answer:
3l+m+5n=0 i.e. m=-(3l+5n) .... (i)
6mn-2nl+5lm=0 ... (ii)
Substituting m in the (ii) eq, we get
(l+n)(l+2n)=0
l=-n or l=-2n


Answered by Renu Varma | 24th Sep, 2019, 10:05: AM
Concept Videos
- prove that vectors -2i -2j+4k , -2i+4j -2k , 4i -2j -2k are coplanar ?
- Find the direction cosines of the line whose direction ratios are 4, – 3, 2 .
- Find the direction cosines of the vector
.&
- Find the direction cosines of the line segment joining the points (2, 0, 1) and (–1, 3, –2).
- Find the angle inclined to Z-axis, where line is inclined to X-axis at 45o and to Y-axis at 60o.
- If a line in the XY-plane makes an angle 60o with X-axis. Find the direction cosines of this line.
- If a line makes angles
with OX, OY and OZ respectively. Prove that
.
- If a line makes angles
with OX, OY and OZ respectively. Prove that
.
- The co-ordinates of the vertices of the triangle are A(–1 0, 3), B(2, – 3, 6) and C(–1, 3, 2). Find the direction cosines of the medians of the triangle
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change