The value of direction cosine of two straight lines can satisfy the two equation, 3l+m+5n=0 & 6mn-2nl+5lm=0 . Find the angle between those lines.
Asked by rsjkumar2003 | 23rd Sep, 2019, 01:09: PM
Expert Answer:
3l+m+5n=0 i.e. m=-(3l+5n) .... (i)
6mn-2nl+5lm=0 ... (ii)
Substituting m in the (ii) eq, we get
(l+n)(l+2n)=0
l=-n or l=-2n
Answered by Renu Varma | 24th Sep, 2019, 10:05: AM
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