Request a call back

The digits of a two-digit number are in the ratio 2:3 and the number obtained by interchanging the digits is greater than the original number by 27.what is the original number?
Asked by sarajagtap959 | 06 Jan, 2019, 12:27: PM
Let the digits are 2x and 3x .
If 2x is unit-place digit and 3x is tenth-place digit, then the number is   (3x)10+2x = 32x
By reversing the digits, number obtained is  (2x)10 + 3x = 23x

Since the difference is 27,  we have  9x = 27  or  x = 3

hence digits are 6 and 9 and original number is 69
Answered by Thiyagarajan K | 06 Jan, 2019, 12:42: PM

## Concept Videos

ICSE 8 - Maths
Asked by vandanarameshthakur | 23 Sep, 2023, 04:48: PM
ICSE 8 - Maths
Asked by kumarpreetham116 | 14 Sep, 2023, 10:44: PM
ICSE 8 - Maths
Asked by kavishree311986 | 12 Sep, 2023, 08:25: PM
ICSE 8 - Maths
Asked by vaishnavinautiyal54 | 07 Sep, 2023, 10:52: AM
ICSE 8 - Maths
Asked by sethiaiyana | 06 Sep, 2023, 10:22: PM
ICSE 8 - Maths
Asked by singharan52 | 05 Sep, 2023, 01:42: PM