tan1 tan2 tan3 ............tan89=1

what is the probability that a leap year selected at random will have 53 sundays

if the polynomial x^4-6x^3+16x^2-26x+10 is divided by another polynomial x^2-2x+k gives reminder x+a . then find a and k.

 

Asked by sanjaysahu675 | 16th Jan, 2019, 10:49: PM

Expert Answer:

tan1 tan2......tan45.....tan88 tan89

= tan1tan2....tan45...tan(90 - 2)tan(90 - 1)                  tan (90 - x) = cot x

= tan1 tan2....tan45....cot2 cot1 
 
= (tan1 cot1) (tan2 cot2) .......tan 45

= 144 × 1                                                                tanx cotx = 1

= 1 
 
= RHS
 
tan1 tan2......tan45.....tan88 tan89 = 1

Answered by Sneha shidid | 17th Jan, 2019, 09:36: AM