CBSE Class 10 Answered
Evaluate cot 12 cot 38 cot 52 cot 60 cot 78
Asked by sadhanapatil494 | 13 Jan, 2020, 08:02: PM
Expert Answer
cot12° cot38° cot52° cot60° cot78°
= (cot12°× cot78°)(cot38° cot52°) cot60°
=[cot12°×cot(90° - 12º)][cot38°×cot(90° - 38º) cot60°
= cot12°× tan12°× cot38°× tan38°× cot60°
= 1 × 1× cot60°
= 1/2
Answered by Yasmeen Khan | 14 Jan, 2020, 10:34: AM
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