strictly increasing function

Asked by imanumaan | 20th Nov, 2009, 05:23: PM

Expert Answer:

consider f(x)=x-[x] on (0,1)

let x1, x2 be two elements in  (0,1)  such that x12

Now f(x1)= x1-[x1] = x1   Greatest integer less than or equal to x1 will be 0

f(x2) =x2-[x2]=x2  

So  f(x1)  < f(x2)   

hence f is strictly increasing


Answered by  | 26th Nov, 2009, 12:29: PM

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