strictly increasing function
Asked by imanumaan
| 20th Nov, 2009,
05:23: PM
Expert Answer:
consider f(x)=x-[x] on (0,1)
let x1, x2 be two elements in (0,1) such that x1
Now f(x1)= x1-[x1] = x1 Greatest integer less than or equal to x1 will be 0
f(x2) =x2-[x2]=x2
So f(x1) < f(x2)
hence f is strictly increasing
Answered by
| 26th Nov, 2009,
12:29: PM
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