Speed of particle increases by 20%.How many percent its kinetic energy increases
Asked by lovemaan5500 | 26th Dec, 2017, 11:23: AM
let the initial velocity be V
20 % increase will be V + 20% of V
KEi = 1/2 m v2
KEf = 1/2 m (1.2v)2
= 1.44 x 1/2 m v2
increase in KE= KEf - KEi = 1.44 x 1/2 m v2 - 1/2x m v2 = 0.44 x 1/2 m v2
percent increase in kinetic energy
Answer is 44 %
Answered by Gajendra | 27th Dec, 2017, 04:49: PM
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