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Asked by adjacentcalliber10 | 08 May, 2019, 11:18: AM
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If t is thickness of slab and μ is the refractive index, it produces a shift of  [1 - (1/μ)]t .
 
Hence in this case shift produced by slab = [1-(2/3)]×6 = 2 cm.
 
Hence objct placed at 27 cm from the concave mirror appears as if it is placed at a distance 25 cm.
 
Image position v is obtained from mirror equation (1/u)+(1/v) = 1/f  
 
Hence (1/v) = (1/20) - (1/25)    or   v = 100
 
Again after reflection light ray is passing through the slab and produces a shift of 2 cm.
 
Hence final image is obtained at 100+2 = 102 cm
Answered by Thiyagarajan K | 09 May, 2019, 06:48: AM

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