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Asked by eknathmote50 | 08 May, 2019, 10:39: AM
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Let the incident light ray makes the angle θ at B on a glass sphere.
If angle of refraction for refracted ray at B is r , then angle of incidence at C also r, because ΔOBC is isoceless.
At C, angle of reflection will be r. Hence angle of emergence at C is (90-r), because emergent ray and reflected ray
are perpendicular to each other.
 
At the point C, by law of refraction, we have  sin(90-r)/sin(r)  = √3   or tan(r) = 1/√3  or r = π/6
 
At the point B,  sin(θ)/sin(r) = sin(θ)/sin(π/6) = √3    or  sin(θ) = √3 /2  or  θ = π/3
Answered by Thiyagarajan K | 08 May, 2019, 15:01: PM

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