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Asked by adjacentcalliber10 | 18 May, 2019, 13:22: PM
answered-by-expert Expert Answer
A) -  P) and T) 
In y- direction, the normal force on the ground can change but there is no external force in x- direction. Thus, momentum is conserved in x-direction and net force on system in x-direction is zero.
 
B) - P), R), S) and T)
 
The normal force on the ground can change but no work is done. Thus, momentum is conserved in x-direction, mechanical energy is conserved, work done by internal forces is zero and net force on system in x-direction is zero.
 
C) - P), Q), R), and T) 
Both charges are free to move. As they are point charges, we can consider it to be elastic collision. Thus, momentum is conserved in x-direction, momentum is conserved in y-direction, mechanical energy is conserved,  and net force on system ihorizontal direction is zero.
 
D) - Q) and R) 
 
Only charge q1 is free to move. As they are point charges, elastic collision is considered. Thus, momentum in y -direction is conserved and mechanical energy is conserved. 
Answered by Shiwani Sawant | 25 May, 2019, 16:55: PM
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