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Asked by sarveshvibrantacademy | 16 May, 2019, 11:45: AM
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For refraction at spherical surface, we have,  begin mathsize 12px style mu over v minus 1 over u equals fraction numerator mu minus 1 over denominator R end fraction end style   .................(1)
where μ is refractive index of spherical medium, v is image distance from pole,
u is object distance from pole and R is radius of curvature.
 
we have μ = 1.5, v = R+(32/3) cm ,  u = -6 cm
 
By substituting the values in eqn.(1), we get , begin mathsize 12px style fraction numerator 1.5 over denominator R plus begin display style 32 over 3 end style end fraction space plus space 1 over 6 space equals space fraction numerator 0.5 over denominator R end fraction end style   ...............(2)
By solving eqn.(2), we get R ≈ 1.74 cm
Answered by Thiyagarajan K | 17 May, 2019, 05:28: AM

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