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Asked by sarveshvibrantacademy | 29 Apr, 2019, 11:12: AM
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Let x cm  is the object distance from lens. Let image is formed at other side of the lens at a distance v cm from lens.
 
Distance v is obtained from lens equation,  (1/v) +(1/x) = 1/30  or  v = 30x/(x-30) cm
 
Since mirror is placed at 15 cm from lens, image is formed at a distance (v-15) cm in front of reflecting surface of mirror.
Hence image distance from lens is (v-30)  = [ 30x/(x-30) ]-30  = 900/(x-30) cm
 
Now this image is acting as object to form image at initial location
 
hence we have   (1/x) + [ (x-30) /900 ] = 1/30    ...............(1)
 
By solving eqn.(1) for x, we get x = 30 cm
Answered by Thiyagarajan K | 29 Apr, 2019, 17:42: PM

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