CBSE Class 10 Answered
solve

Asked by singhshrey918 | 29 Dec, 2020, 10:23: PM
(i)
If we multiply each observation by 5, the new mean would be 5 times the original mean.
Therefore, new mean is 

(ii)
The class with the maximum frequency is said to be modal.
(iii)
Concentration of SO2 (in ppm) | Frequency | Class mark xi | di = xi - 0.14 | ![]() |
fiui |
0.00 - 0.04 | 4 | 0.02 | -0.12 | -3 | -12 |
0.04 - 0.08 | 9 | 0.06 | -0.08 | -2 | -18 |
0.08 - 0.12 | 9 | 0.10 | -0.04 | -1 | -9 |
0.12 - 0.16 | 2 | 0.14 | 0 | 0 | 0 |
0.16 - 0.20 | 4 | 0.18 | 0.04 | 1 | 4 |
0.20 - 0.24 | 2 | 0.22 | 0.08 | 2 | 4 |
Total | 30 | -31 |
(iv)
The median class of the given data is 0.08 - 0.12
Answered by Renu Varma | 30 Dec, 2020, 11:35: AM
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