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Asked by eknathmote50 | 07 May, 2019, 11:18: AM
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Image due to plane mirror is at a distace x behind the plane mirror.
If image due to convex mirror coincide with image due to plane mirror,
then image-to-mirror distance for convex mirror is (y-x).
 
we have mirror equation for convex mirror,  (1/u) + (1/v) = 1/f ...............(1)
 
where u is object-to-mirror distance which is given by, u = -(x+y)  [ sign convention is applied ]
v is image-to-mirror distance which is given by, v = -(y-x) = (x-y)  [ sign convention is applied ]
 
hence from (1), we have   [ 1/(x-y) ] - [ 1/(x+y) ] = 1/f ...............(2)
 
After simpification, we get from eqn.(2),  f = ( x2 - y2 ) / (2y) 
Answered by Thiyagarajan K | 07 May, 2019, 18:16: PM

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