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Asked by eknathmote50 | 07 May, 2019, 11:18: AM
Expert Answer
Image due to plane mirror is at a distace x behind the plane mirror.
If image due to convex mirror coincide with image due to plane mirror,
then image-to-mirror distance for convex mirror is (y-x).
we have mirror equation for convex mirror, (1/u) + (1/v) = 1/f ...............(1)
where u is object-to-mirror distance which is given by, u = -(x+y) [ sign convention is applied ]
v is image-to-mirror distance which is given by, v = -(y-x) = (x-y) [ sign convention is applied ]
hence from (1), we have [ 1/(x-y) ] - [ 1/(x+y) ] = 1/f ...............(2)
After simpification, we get from eqn.(2), f = ( x2 - y2 ) / (2y)
Answered by Thiyagarajan K | 07 May, 2019, 06:16: PM
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