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Asked by adjacentcalliber10 | 25 May, 2019, 20:15: PM
answered-by-expert Expert Answer
G i v e n colon space x plus y equals x to the power of y
rightwards double arrow log left parenthesis x plus y right parenthesis equals log space x to the power of y
rightwards double arrow log left parenthesis x plus y right parenthesis equals y space log space x
rightwards double arrow fraction numerator 1 over denominator x plus y end fraction open parentheses 1 plus fraction numerator d y over denominator d x end fraction close parentheses equals y 1 over x plus log space x space fraction numerator d y over denominator d x end fraction
rightwards double arrow fraction numerator 1 over denominator x plus y end fraction plus fraction numerator 1 over denominator x plus y end fraction times fraction numerator d y over denominator d x end fraction equals y over x plus log space x space times space fraction numerator d y over denominator d x end fraction
rightwards double arrow open parentheses fraction numerator 1 over denominator x plus y end fraction minus log space x close parentheses fraction numerator d y over denominator d x end fraction equals y over x minus fraction numerator 1 over denominator x plus y end fraction
rightwards double arrow fraction numerator d y over denominator d x end fraction equals fraction numerator y over x minus fraction numerator 1 over denominator x plus y end fraction over denominator fraction numerator 1 over denominator x plus y end fraction minus log space x end fraction
Answered by Renu Varma | 27 May, 2019, 10:26: AM
JEE main - Maths
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