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Asked by sarveshvibrantacademy | 10 May, 2019, 10:22: AM
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As shown in figure, when the cylinderical container is not filled with liquid,
 
angle of emergence θ for the top of board at the right edge of container is given by, tanθ = 2  or sinθ = 2/√5
 
After filling the container with liquid, bottom of the board is seen due to refraction.
If begin mathsize 12px style ϕ end style is angle of incidence at liquid-air boundary for the light ray going from bottom of the board,
then we have tanbegin mathsize 12px style ϕ end style = 1  or  sinbegin mathsize 12px style ϕ end style = 1/√2
refractive index of liquid  μ = sinθ / sinbegin mathsize 12px style ϕ end style  = 2√2 / √5
Answered by Thiyagarajan K | 11 May, 2019, 09:40: AM

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