# CBSE Class 10 Answered

**solve x + y + z + u = 120 , 2x + y + 4 z+ 3y = 29 , 3x + 2y +z + 4u= 27, 4x + 3y +z +2u = 22. find x,y .z. u**

Asked by viraat.verma26 | 14 May, 2021, 01:10: PM

Expert Answer

GIven:

x + y + z + u = 120 ... (1)

2x + y + 4z + 3u = 29 ... (2)

3x + 2y + z + 4u = 27 ... (3)

4x + 3y + z + 2u = 22 ... (4)

(1) - (2), we get, -x - 3z - 2u = 91 ... (i)

(3) - (4), we get, -x - y + 2u = 5 ... (ii)

Using (1) and (3), we get, -x + z - 2u = 213 ... (iii)

Using (2) and (4), we get, 2x + 11z + 7u = 65 ... (iv)

Solving (i) and (iii), we get

z = 61/2

Use these equations and find the values of remaining variables.

Answered by Renu Varma | 17 May, 2021, 06:06: PM

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