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solve x + y + z + u = 120 , 2x + y + 4 z+ 3y = 29 , 3x + 2y +z + 4u= 27, 4x + 3y +z +2u = 22. find x,y .z. u
Asked by viraat.verma26 | 14 May, 2021, 01:10: PM
GIven:
x + y + z + u = 120   ... (1)
2x + y + 4z + 3u = 29   ... (2)
3x + 2y + z + 4u = 27   ... (3)
4x + 3y + z + 2u = 22   ... (4)

(1) - (2), we get,  -x - 3z - 2u = 91   ... (i)

(3) - (4), we get,  -x - y + 2u = 5     ... (ii)

Using (1) and (3), we get,   -x + z - 2u = 213   ... (iii)

Using (2) and (4), we get,   2x + 11z + 7u = 65  ... (iv)

Solving (i) and (iii), we get
z = 61/2

Use these equations and find the values of remaining variables.
Answered by Renu Varma | 17 May, 2021, 06:06: PM

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