CBSE Class 10 Answered
solve x + y + z + u = 120 , 2x + y + 4 z+ 3y = 29 , 3x + 2y +z + 4u= 27, 4x + 3y +z +2u = 22. find x,y .z. u
Asked by viraat.verma26 | 14 May, 2021, 13:10: PM
GIven:
x + y + z + u = 120 ... (1)
2x + y + 4z + 3u = 29 ... (2)
3x + 2y + z + 4u = 27 ... (3)
4x + 3y + z + 2u = 22 ... (4)
(1) - (2), we get, -x - 3z - 2u = 91 ... (i)
(3) - (4), we get, -x - y + 2u = 5 ... (ii)
Using (1) and (3), we get, -x + z - 2u = 213 ... (iii)
Using (2) and (4), we get, 2x + 11z + 7u = 65 ... (iv)
Solving (i) and (iii), we get
z = 61/2
Use these equations and find the values of remaining variables.
Answered by Renu Varma | 17 May, 2021, 18:06: PM
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