Request a call back

Join NOW to get access to exclusive study material for best results

JEE Class main Answered

Solve the question in photo...
question image
Asked by Vidushi412 | 31 Mar, 2019, 21:10: PM
answered-by-expert Expert Answer
Numerator   Nr = | sin x | - |cos x| varies from -1 to +1
 
Nr = -1  ,  when x = nπ  ,  where n = 0, 1, 2......
 
Nr = +1 , when  x = n (π/2) , where n = 1,2,3,.........
 
when Nr reaches the extreme values -1 or +1, Denominator Dr = | sin x | + |cos x| = 1
 
Denominator function Dr varies from 1 to 1.5  .
Since sin x and cos x are complimentary function i.e when one of them reaches maximum 1 otherone will be at minimum 0,
their sum always start from 1 and maximum 1.5 occurs , when | sin x | and | cos x | both are equal , ie at x= (2n+1)(π/4), n=0,1,2,3...
when denominator reaches maximum 1.5, Numerator is zero.
 
Hence overall effect of the function is it varies from minimum value  -1 to maximum value +1,
mimimum occurs at x = nπ , n=0,1,2......
maximum occurs at x = (2n+1)(π/2) , n =0,1,2...
 
hence difference between sucessive minimum or maximum is π .  Hence period is π
Answered by Thiyagarajan K | 01 Apr, 2019, 10:29: AM
JEE main - Maths
Asked by pallavibirangal87 | 08 Dec, 2024, 10:18: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Maths
Asked by pritisindra6 | 06 Dec, 2024, 21:04: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Maths
Asked by pawandhayal125 | 06 Oct, 2024, 10:03: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Maths
Asked by srishtipra2008 | 28 Sep, 2024, 10:33: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Maths
Asked by yogeshsoni575 | 23 Sep, 2024, 23:01: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Maths
Asked by pritamlovevanshi5 | 15 Sep, 2024, 08:24: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Maths
Asked by ganeshbabugottapu7 | 12 Sep, 2024, 18:19: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Maths
Asked by ganeshbabugottapu7 | 10 Sep, 2024, 07:32: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT