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solve the following
Asked by sarveshvibrantacademy | 05 Apr, 2019, 10:28: AM
Expert Answer
youngs modulus Y = ................(1)
where T is tension subjected by wire, A is area of cross section of wire, Δl is change in length and l is original length.
when the peg is turned for one quarter, Δl = (1/4)π×5×10-3 m = 1.25π×10-3 m
from eqn.(1) , we get T as, T = Y×(Δl/l)×A = 20×1010 × [ (1.25π×10-3 ) / (6×10-2 ) ]×(π/4)×(8×10-4)2 ≈ 6580 N
Linear mass density, μ = mass of unit length of string = (π/4)×(8×10-4)2 × 1 × 7800 = 98×10-5 kg/m
velocity of transverse wave, v =
for fundamental mode, wavelength λ = 2l = 2 × 6×10-2 m = 12× 10-2 m
fundamental frequency, n = v/λ = 2591/ (12× 10-2 ) = 21592 Hz = 21.6 kHz
Answered by Thiyagarajan K | 05 Apr, 2019, 02:15: PM
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