Solve it

Asked by Thakurakash.atmt93698 | 8th Feb, 2019, 11:31: AM

Expert Answer:

begin mathsize 16px style straight I equals integral fraction numerator cos 2 xsin 4 xdx over denominator 1 plus cos squared 2 straight x end fraction end style
begin mathsize 16px style straight I equals integral fraction numerator cos 2 straight x open parentheses 2 sin 2 xcos 2 straight x close parentheses dx over denominator 1 plus cos squared 2 straight x end fraction end style
cos2x = t
-2sin2xdx = dt
begin mathsize 16px style sin 2 xdx equals fraction numerator negative dt over denominator 2 end fraction end style
begin mathsize 16px style straight I equals integral fraction numerator 2 straight t squared begin display style fraction numerator negative dt over denominator 2 end fraction end style over denominator 1 plus straight t squared end fraction end style
begin mathsize 16px style straight I equals negative integral fraction numerator straight t squared dt over denominator 1 plus straight t squared end fraction end style
Integrate it further.

Answered by Sneha shidid | 11th Feb, 2019, 10:21: AM