Sir, you have solved the following question: ??e^(-x) cos2xcos4xdx? But, I am not able to solve it further. So please solve it fully giving full explanation. The answer to this question given in the book is: e^(-x) [1/74 (6sin6x-cos6x)+1/10 (2sin2x-cos2x)]+C

Asked by Manoj | 24th Mar, 2013, 05:13: PM

Expert Answer:

Answered by  | 24th Mar, 2013, 10:07: PM

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