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![question image](https://images.topperlearning.com/topper/new-ate/topr_933652642223642201907301159491.jpeg)
Asked by vishakhachandan026 | 30 Jul, 2019, 18:28: PM
Given:
For hydrogen,
Volume = 0.5 m3
Temperature = 20.5 °C
=273 + 20.5 = 293.5 K
Pressure = 611 × 103 Pa
Calculate no.of moles by using gas law,
![PV space equals nRT
space space straight n space equals PV over RT
space space space space space space equals fraction numerator 611 cross times 10 cubed cross times 0.5 over denominator 293.5 cross times 8.314 end fraction
space space straight n space space equals 125 space mol](https://images.topperlearning.com/topper/tinymce/cache/5cea902a6f0a5b7b5eb8cb06c74e8673.png)
For argon,
Volume = 0.750 m3
Temperature =31.2 °C
= 273 + 31.2=304.2 K
Pressure = 433 × 103 Pa
Calculate no.of moles by using gas law,
PV =nRT
![straight n equals PV over RT
space space space equals fraction numerator 433 cross times 10 cubed cross times 0.75 over denominator 8.314 cross times 304.2 end fraction
straight n space equals 128 space mol](https://images.topperlearning.com/topper/tinymce/cache/98ee525900d01c7ee4bfc0a097264cf4.png)
Total no. of moles = 125+128 = 253 mole
Final temperature = 14.5 °C
Final volume = 0.5 +0.75 = 1.25 m3
= 273 + 14.5 =287.5 K K
PV = nRT
![straight P equals nRT over straight V
space space space equals fraction numerator 253 cross times 8.314 cross times 287.5 over denominator 1.25 end fraction
straight P space equals space 4.837 cross times 10 to the power of 5 space end exponent Pa](https://images.topperlearning.com/topper/tinymce/cache/db87f9954fe1eb9c54a062c6cdfddb11.png)
The final pressure of the vessle is 4.837 × 105 Pa
Answered by Varsha | 02 Aug, 2019, 12:30: PM
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