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JEE Class main Answered

Sir pls solve the following.

Asked by rsudipto | 26 Dec, 2018, 11:35: AM
Expert Answer
Use R1 → R1 - R2 and R2 → R2 - R3
Then use formulae to simplify it further
 begin mathsize 16px style sinC minus sinD equals 2 cos open parentheses fraction numerator straight C plus straight D over denominator 2 end fraction close parentheses sin open parentheses fraction numerator straight C minus straight D over denominator 2 end fraction close parentheses
cosC minus cosD equals 2 sin open parentheses fraction numerator straight C plus straight D over denominator 2 end fraction close parentheses sin open parentheses fraction numerator straight D minus straight C over denominator 2 end fraction close parentheses
Taking space 2 sin open parentheses fraction numerator straight alpha minus straight beta over denominator 2 end fraction close parentheses space from space straight R subscript 1 space and space 2 sin open parentheses fraction numerator straight beta minus straight lambda over denominator 2 end fraction close parentheses space from space straight R subscript 2
Solve space the space determinant space you space will space get space expression space which space is space independent space of space straight theta. end style
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