JEE Class main Answered
Sir pls solve the following.
Asked by rsudipto | 03 Jan, 2019, 01:02: PM
Expert Answer
Loss of thermal energy for the water when it is cooled for every ΔT=5°C = m×Cp×ΔT Joules
radiated thermal power from water when it is cooled from 75° C to 70° C = σA(754 - 704) Watts
hence time taken to cool from 75° C to 70° C = 
( we are given that this time is T1 minutes)
Hence T1 
1/(754 - 704 )
1/(754 - 704 )similarly we can write, T2 1/(704 - 654 )
1/(704 - 654 )similarly we can write, T3 1/(654 - 604 )
1/(654 - 604 )Hence it is obvious that T1 < T2 < T3
Answered by Thiyagarajan K | 03 Jan, 2019, 02:46: PM
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