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Sir pls solve the following.
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Asked by rsudipto | 29 Dec, 2018, 11:47: AM
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begin mathsize 12px style S i n c e space open vertical bar z subscript 1 close vertical bar space equals space open vertical bar z subscript 2 close vertical bar space equals 1 comma space w e space w r i t e z subscript 1 space equals space a plus i b space equals space cos space theta subscript 1 space plus space i space sin space theta subscript 1 space space space space space z subscript 2 space equals space c space plus space i d space equals space cos theta subscript 2 space plus i space sin theta subscript 2 stack z subscript 2 with bar on top space space equals space c space minus space i d space equals space cos theta subscript 2 space minus space i space sin theta subscript 2 R e open parentheses Z subscript 1 stack Z subscript 2 with bar on top close parentheses space space equals space cos theta subscript 1 space cos theta subscript 2 space plus space sin theta subscript 1 space sin theta subscript 2 space equals space cos open parentheses theta subscript 1 minus theta subscript 2 close parentheses space equals space 0 h e n c e space theta subscript 1 minus theta subscript 2 space equals space pi over 2 space o r space theta subscript 1 space equals space pi over 2 plus space theta subscript 2 n o w space w subscript 1 space equals space a plus space i space c space equals space cos theta subscript 1 space plus space i space cos theta subscript 2 space equals space cos open parentheses pi over 2 plus space theta subscript 2 close parentheses space plus space i space cos theta subscript 2 space equals space minus sin theta subscript 2 space plus space i space cos theta subscript 2 w subscript 2 space equals space b plus space i space d space equals space sin theta subscript 1 space plus space i space sin theta subscript 2 space equals space sin open parentheses pi over 2 plus space theta subscript 2 close parentheses space plus space i space sin theta subscript 2 space equals space cos theta subscript 2 space plus space i space sin theta subscript 2 i t space c a n space b e space s e e n space f r o m space t h e space e x p r e s s i o n space f o r space w subscript 1 space a n d space w subscript 2 comma space open vertical bar w subscript 1 close vertical bar space equals space open vertical bar w subscript 2 close vertical bar space equals space 1 stack w subscript 2 with bar on top space equals space cos theta subscript 2 space minus space i space sin theta subscript 2 R e left parenthesis w subscript 1 stack w subscript 2 with bar on top space right parenthesis space equals space minus sin theta subscript 2 cos theta subscript 2 space plus space sin theta subscript 2 cos theta subscript 2 space equals space 0 end style
 
Hence correct statement is (C)
Answered by Thiyagarajan K | 30 Dec, 2018, 03:28: PM

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