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Sir, pls solve the following.
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Asked by rsudipto | 23 Dec, 2018, 09:09: AM
answered-by-expert Expert Answer 
a = 2A +1
b = 2B +1
c = 2C +1
Now
2(2A + 1 + 2B + 1 + 2C + 1) = 10
A + B + C = 5
Now
A, B, C can start from 0
Now
A.     B     C
0      0     5  →      3 ways
0      1     4 →      6 ways
0      2     3  →     6 ways
1      1     3 →     3 ways
1      2     2  →     3 ways
 
Hence total possible numbers are 21.
Answered by Sneha shidid | 24 Dec, 2018, 09:51: AM

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