CBSE Class 12-science Answered
sir please solve in detail ,,,,it is from inverse trignometric function..
Asked by | 29 Oct, 2009, 03:38: PM
Expert Answer
tan 1/2 [ sin-12x/1+x2 + cos-1 1-y2/1+y2 ]
since sin-12x/1+x2 =2 tan-1 x and 2tan-1 y = cos-1 (1-y2/1+y2 )
tan 1/2[2 tan-1 x +2tan-1 y]= tan[tan-1 x+tan-1 y]
using tan-1 x+tan-1 y = tan-1 (x+y)/(1-xy)
= tan[tan-1 (x+y)/(1-xy)]=x+y/(1-xy)
Answered by | 05 Nov, 2009, 11:40: AM
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