JEE Class main Answered
sir please answer this question
In a young`s double slit experiment'slits are seperated by 0.5mm, and the screen is place 150 cm away. A beam of light consisting of two wavelengths, 650nm and 520 nm, is used to obtain fringes on the screen . the least distance from common central maximum to the point were the bright fringes due to both the wavelngths coincide is
Asked by ppavani198 | 29 Dec, 2018, 06:37: PM
Expert Answer
Let λ1 = 650 nm and λ2 = 520 nm are the two wavelenths present in the light beam.
Let bright fringe number n1 of λ1 coincide with fringe number n2 of λ2 .
Let D is the distance between slit and screen and d is interdistance between slits.
Then we have
Hence the required minimum distance from central maximum is
Answered by Thiyagarajan K | 30 Dec, 2018, 10:42: AM
Application Videos
JEE main - Physics
Asked by srkgb8018 | 05 May, 2024, 10:12: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by sandhyapallapu22 | 03 May, 2024, 04:32: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by gamingbadboy085 | 01 May, 2024, 06:28: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by bhargavreddynellaballi | 30 Apr, 2024, 08:18: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ravichandraravula66 | 29 Apr, 2024, 11:20: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by kmani310507 | 28 Apr, 2024, 04:38: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by arivaryakashyap | 23 Apr, 2024, 10:40: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ratnadeep.dmr003 | 21 Apr, 2024, 11:06: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ksahu8511 | 19 Apr, 2024, 11:55: AM
ANSWERED BY EXPERT