sin B = 1/5sin(2A+B), then d value of tan(A+B)/tanA = ..........??

Asked by SHIVANI_SOOD | 14th Apr, 2010, 05:29: PM

Expert Answer:

5sinB = sin(2A+B)

5sin(A+B-A) = sin(A+A+B)

5{sin(A+B)cosA - cos(A+B) sinA} = sinAcos(A+B) + cosA sin(A+B)

6sinAcos(A+B) = 4cosA sin(A+B)
Dividing by sinAcos(A+B), and rearranging,

tan(A+B)/tanA = 6/4 = 3/2.

Regards,

Team,

TopperLearning.

Answered by  | 16th Apr, 2010, 02:22: PM

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